All categories

3 years ago

Choose 1 answer:

Mathematics

2 answers:

Paladinen [302]3 years ago

6 0

Answer:

B complementary angles

Step-by-step explanation:

ED is a line.

Angles EAB and DAB are a linear pair, so they are supplementary.

Angle EAB is a right angle, so angle DAB is also a right angle.

The measure of angle DAB is 90 degrees.

The sum of the measures of angles a and b is 90 degrees.

That makes <a and <b complementary angles.

Lena [83]3 years ago

3 0

Answer:

the answer is B

Step-by-step explanation:

You might be interested in

Find the area of this parallelogram.

Grace [21]

Answer: A
i hope it helped

3 0

3 years ago

You own a rectangular home lot that is 46,200 square feet in size. You get a quote of $10 per foot. If your lot is 220ft long an

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

width=46200÷220=210 ft

what you mean by quote? i don't know.

3 0

3 years ago

In basketball, some baskets are worth two points. Others are worth three points. In one game, the ratio of three-point basket

fgiga [73]

Answer:

36 attempts

Step-by-step explanation:

7 0

2 years ago

As mercury revolves around the sun, it travels at a speed of approximately 30 miles per second. Convert this speed to kilometers

Elza [17]

30*1.6 = 48 km per second

48 * 2 = 96 kilometres

6 0

3 years ago

Read 2 more answers

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago