Question

Find the discriminant of the following equation. 4x2 + 16x + 16 = 0 ...?

Answer 1

To find the discriminant of the following equation you have to remember tha main formula :  ax^2 +bx + c and the one for discriminant is  b^2 -4ac
So, now we can solve it $16^2 -4(16)(4) = 4^2-4(4)$
$(4^2)^2 -4(4)(4)(4)-4^2 +4(4) = 0$
$4^4 - 4^4 = 0$$16^2-4*4*16=0$ , so the discriminants is 0 :) 
Hope it's clear!

Answer 2

Answer:

The discriminant is 0.

Step-by-step explanation:

Since, the discriminant of a quadratic equation $ax^2+bx+c=0$ is,

$D=b^2-4ac$

Here, the given equation is,

$4x^2+16x+16=0$

By comparing,

a = 4, b = 16 and c = 16,

Hence, the discriminant of the given equation is,

$16^2-4\times 4\times 16$

$=256 - 256$

$=0$