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4 years ago

The product of a nonzero rational number and an irrational number

2 answers:

4 0

Since irrational numbers are forever going, multiplying any nonzero rational number with an irrational number will make the product irrational as well

coldgirl [10]4 years ago

3 0

Answer:

The product of a non-zero rational number and an irrational number is irrational.

Step-by-step explanation:

If you multiply any irrational number by the rational number zero, the result will be zero, which is rational.

However, the product of a non-zero rational number and an irrational number is irrational.

Example-

$5/6\times3.14=2.616666666...$

So, its irrational.

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17.031 times what would give me 3.5 (17.031x = 3.5)

Misha Larkins [42]

Answer:

4.78

Step-by-step explanation:

8 0

3 years ago

The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains poi

kozerog [31]

$y=mx+b\\\\
5=5\cdot4+b\\
b=5-20=-15\\\\
\boxed{y=5x-15}$

4 0

3 years ago

Read 2 more answers

Please help, the question below

Licemer1 [7]

Answer:

$\sf R=\left(3, -\dfrac{5}{4}\right)$

Step-by-step explanation:

Given:

P = (1, 5)
Q = (-2, 3)
R = (a, b)
R lies on line x = 3
PR = QR

If point R lies on the line x = 3, then the x-value of point R is 3.

⇒ a = 3

Distance between two points

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

(where (x₁, y₁) and (x₂, y₂) are the two points)

Use the distance formula to derive equations for PR and QR.

Let (x₁, y₁) = P = (1, 5)

Let (x₂, y₂) = R = (3, b)

$\begin{aligned} \sf PR & =\sf \sqrt{(3-1)^2+(b-5)^2}\\ & = \sf \sqrt{4+(b-5)^2} \end{aligned}$

Let (x₁, y₁) = Q = (-2, 3)

Let (x₂, y₂) = R = (3, b)

$\begin{aligned} \sf QR & =\sf \sqrt{(3-(-2))^2+(b-3)^2}\\ & = \sf \sqrt{25+(b-3)^2} \end{aligned}$

As PR = QR, equate the derived equations and solve for b:

$\begin{aligned} \sf PR & = \sf QR \\\sf \sqrt{4+(b-5)^2} & = \sf \sqrt{25+(b-3)^2}\\\sf 4+(b-5)^2 & = \sf 25+(b-3)^2\\\sf 4+b^2-10b+25 & = \sf 25 + b^2-6b+9\\\sf b^2-10b+29 & = \sf b^2 -6b +34\\\sf -10b+29 & = \sf -6b + 34\\\sf -4b & = \sf 5\\\sf b & = -\dfrac{5}{4}\end{aligned}$

Substitute the found values of a and b to find the coordinates of R:

$\sf R=(a,b)=\left(3, -\dfrac{5}{4}\right)$

Learn more about the distance formula here:

brainly.com/question/28144723

8 0

2 years ago

Read 2 more answers

Using the Vertical Method to multiply these two polynomials, fill in the values for A, B, and C

yawa3891 [41]

Answer:

A = 8x^2

B = 6x^3

C = -23x

Step-by-step explanation:

A: -4 * -2x^2

A: 8x^2

B: -3x * -2x^2

B: 6x^3

C: -8x -15x

C: -23x

Hope this helps!

4 0

3 years ago

Radium-226 is a metal with a half-life of 1600 years. If you start with 1 kilogram of radium-226, how much will remain after 20,

erica [24]

Ending Amount = Beginning Amount / 2^n
where 'n' = # of half lives
n = 20,000 / 1,600 = 12.5 half-lives

Ending Amount = 1 kg / 2^12.5
Ending Amount = 1 kg / 5,792.6
Ending Amount = 0.00017263 kilograms = 0.17263 grams

6 0

4 years ago