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3 years ago

(Write the equation for the line that goes through -3,-3) slope 7/3

1 answer:

3 0

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-3})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{7}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{7}{3}}[x-\stackrel{x_1}{(-3)}] \implies y+3=\cfrac{7}{3}(x+3) \\\\\\ y+3=\cfrac{7}{3}x+7\implies y=\cfrac{7}{3}x+4$

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tamaranim1 [39]

Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

If sin phi sin theta = 0.2 and sin phi cos theta = -0.3 and sin phi > 0 what is theta ? Repeat for sin phi < 0.

Rina8888 [55]

Answer:

θ = -33.69°

Step-by-step explanation:

For Φ>0 and Φ<0 (in general Φ≠nπ where n is an integer), sin(Φ) ≠ 0

Dividing both equations:

$\frac{sin(\phi) sin(\theta)}{sin(\phi)cos(\theta)} = tan(\theta) = 0.2/(-0.3)=-2/3\\$

Therefore:

arctan(θ) = -2/3

θ = -33.69°

The answer does not depend on the sign of Φ, in fact we just need that the sine does not become zero, which occurs when Φ is equal to an integer times π (radians) or 180 (degrees)

Have a nice day!

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3 years ago

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garri49 [273]

Answer:

Step-by-step explanation:

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3 years ago