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nexus9112 [7]
3 years ago
8

What is the solution to the system of equations below?

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0

Answer:

c

Step-by-step explanation:

Agata [3.3K]3 years ago
4 0

Answer:

The answer is C

Step-by-step explanation:

Use the method of elimination

First rearrange the first equation to look like the second

2x + 3y = 17 \\ 4x + 6y = 34 \\  - 4x - 6y =  - 34

Next add the two equations together eliminating the <em>y</em> term.

- 4x - 6y =  - 34 \\ 3x + 6y = 30 \\  \\  - x =  - 4 \\ x = 4

There's only one answer with x = 4 so you're done. To go further, substitute x = 4 into the second equation and solve for y

3x + 6y = 30 \\ 3 \times 4 + 6y = 30 \\ 12 + 6y = 30 \\ 6y = 18 \\ y = 3

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x = 9

Step-by-step explanation:

5x - 15 + 2x = 4x + 12

7x - 4x = 12 + 15

3x = 27

x = 9

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The drama club is selling tickets for a play. The profit, y, is
Goshia [24]

Answer:

80 tickets

Step-by-step explanation:

Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of  tickets, x, that need to be sold for the drama club to break  even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;

y = x^2 – 40x – 3,200,

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x^2 – 80x  + 40x – 3,200 = 0

x(x-80)+40(x-80) = 0

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Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
What does 11 meters equal in centimeters
joja [24]
The answer is 1100 centimeters.
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3 years ago
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