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RoseWind [281]
3 years ago
5

Sherri rolls a dice, numbered 1 to 6, 64 times. How many times can she expect to roll an odd number?

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

32

Step-by-step explanation:

Possible outcomes in a fair sided die 1,2,3,4,5,6 = 6 possible outcomes

Odd numbers = 1,3,5 = 3 odd numbers

Probability of rolling an odd number = \frac{3}{6} = \frac{1}{2}

Total number of rolls = 64

expected number of odd number rolls in 64 roll,

= \frac{1}{2} x 64 = 32

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Answer:

x = 1 - 5t

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Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

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Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

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r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

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We get the parametric equation from this.

x = x(0) + tx'(0)

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y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

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A parabola can be drawn given a focus of (-4, 4) and a directrix of y = –6. Write

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