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RoseWind [281]
3 years ago
5

Sherri rolls a dice, numbered 1 to 6, 64 times. How many times can she expect to roll an odd number?

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

32

Step-by-step explanation:

Possible outcomes in a fair sided die 1,2,3,4,5,6 = 6 possible outcomes

Odd numbers = 1,3,5 = 3 odd numbers

Probability of rolling an odd number = \frac{3}{6} = \frac{1}{2}

Total number of rolls = 64

expected number of odd number rolls in 64 roll,

= \frac{1}{2} x 64 = 32

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astraxan [27]

Answer:

The percentage of people should be seen by the doctor between 13 and

17 minutes is 68% ⇒ 2nd term

Step-by-step explanation:

* Lets explain how to solve the problem

- Wait times at a doctor's office are typically 15 minutes, with a standard

 deviation of 2 minutes

- We want to find the  percentage of people should be seen by the

 doctor between 13 and 17 minutes

* To find the percentage we will find z-score

∵ The rule the z-score is z = (x - μ)/σ , where

# x is the score

# μ is the mean

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∵ The mean is 15 minutes and standard deviation is 2 minutes

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∵ The people should be seen by the doctor between 13 and

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∵ x = 13 and 17

∴ z = \frac{13-15}{2}=\frac{-2}{2}=-1

∴ z = \frac{17-15}{2}=\frac{2}{2}=1

- Lets use the standard normal distribution table

∵ P(z > -1) = 0.15866

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∴ P(-1 < z < 1) = 0.84134 - 0.15866 = 0.68268 ≅ 0.68

∵ P(13 < x < 17) = P(-1 < z < 1)

∴ P(13 < x < 17) = 0.68 × 100% = 68%

* The percentage of people should be seen by the doctor between

  13 and 17 minutes is 68%

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