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NARA [144]
3 years ago
14

a courier earns a fixed amount for each package she delivers and yesterday her average hourly wage was $12.50 an hour if she wor

ked 8 hours yesterday and delivered 25 packages how much does she earn for each package delivered?
Mathematics
2 answers:
enyata [817]3 years ago
5 0
12.50x8=100
100\25=4
awnser is $4.00
Reil [10]3 years ago
4 0

Answer: She earned $ 4 for each package delivered.

Step-by-step explanation:

Since, her total rate of earning = $ 12.50 per hours,

And, she worked for 8 hours.

⇒ She earned in 8 hours = 8 × 12.50 = $ 100

According to the question,

She delivered 25 packages in 8 hours.

⇒ 25 packages = 8 hours

⇒ 25 packages = $ 100

⇒ 1 package = $ 4

Thus, she earned 4 dollars for each package.

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I need this answer step by step but if you can't that's fine too!
Naily [24]
Since the scale factor is 0.5, it means that you have to divide in half each side.
x= 7/2= 3.5
y= 12/2= 6
z= 6/2= 3.25
6 0
4 years ago
Given b= 4 and c= -5, evaluate b2 - c2.<br> 41<br> -2<br> -9
irina [24]

Answer:

-9

Step-by-step explanation:

b² - c²

= 4² - (-5)²

= 16 - 25

= -9

4 0
3 years ago
Brainliest + 20 pts to whoever helps pls!!
Blizzard [7]

Answer:

Correct option is (a). 60.391 and 101.879; because the test statistic is in a critical region, the test rejects the null hypothesis.

Step-by-step explanation:

A Chi-square test for population variance is used to perform this test.

The standard deviation is, 2.0 minutes.

Then the variance is, 4.0 minutes.

The hypothesis for this test is:

<em>H₀</em>: The population variance of all commute times is equal to 4.0 minutes, i.e. <em>σ² </em>= 4.

<em>Hₐ</em>: The population variance of all commute times is not equal to 4.0 minutes, i.e. <em>σ² </em>≠ 4.

The test statistic is:

\chi^{2}_{calc.}=\frac{(n-1)s^{2}}{\sigma^{2}}

The critical region of this test is defined as:

Reject <em>H₀</em> if \chi^{2}_{calc.} or \chi^{2}_{calc.}>\chi^{2}_{(1-\alpha /2), (n-1)}.

The degrees of freedom is:

n-1=81-1=80

Compute the critical from a Chi-square table.

\chi^{2}_{\alpha /2, (n-1)}=\chi^{2}_{0.05, 80}=101.879\\\chi^{2}_{(1-\alpha /2), (n-1)}=\chi^{2}_{0.95, 80}=60.391\\

The test statistic value is, \chi^{2}_{calc.}=105.8.

\chi^{2}_{calc.}=105.8 > \chi^{2}_{0.05, 80}=101.879

The null hypothesis is rejected because the test statistic is in the critical region.

Thus, the correct option is (a).

6 0
3 years ago
The area of a rectangle is 78 square meters. The length of the rectangle is one more than twice the width. What are the dimensio
crimeas [40]

area \:  = 78

area = length \:  \times  \: width

78 = (x)(2x + 1)

x = 6

Thus the dimensions are 6 & 13

3 0
3 years ago
Read 2 more answers
ENROLLMENT The enrollment at Grove
maks197457 [2]

Answer: I believe the answer is 800 students

Step-by-step explanation:

6 0
3 years ago
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