
We have, Discriminant formula for finding roots:

Here,
- x is the root of the equation.
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
1) Given,
3x^2 - 2x - 1
Finding the discriminant,
➝ D = b^2 - 4ac
➝ D = (-2)^2 - 4 × 3 × (-1)
➝ D = 4 - (-12)
➝ D = 4 + 12
➝ D = 16
2) Solving by using Bhaskar formula,
❒ p(x) = x^2 + 5x + 6 = 0



So here,

❒ p(x) = x^2 + 2x + 1 = 0



So here,

❒ p(x) = x^2 - x - 20 = 0



So here,

❒ p(x) = x^2 - 3x - 4 = 0



So here,

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Answer:
See below.
Step-by-step explanation:
It would take a long time to explain . There is a good method called Newton's method which involves graphs of the type
y = x^3 - n and applying calculus to produce cycles of approximation until you'll get close to the required cubic root.
You'll find it on online videos.
Answer:
6^-13
Step-by-step explanation:
The rule for multiplying numbers with the same base but different exponents is a^b*a^c=a^(b+c), so in this case we have 6^(-4+(-9)) which is 6^-13
Hope this helped!