Answer: The solution is (3, -2)
This means that x = 3 and y = -2 pair up together.
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Explanation:
The solution is where the two lines cross. Note if we started at the origin (0,0) and moved to the right 3 units, and then down 2 units, we would arrive at the location (3, -2).
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As a way to check, we can plug x = 3 into each equation. We should get y = -2 as a result for each equation
y = (-5/3)x + 3
y = (-5/3)*3 + 3
y = -5+3
y = -2
The first equation is confirmed. Let's check the second equation
y = (1/3)x - 3
y = (1/3)*3 - 3
y = 1 - 3
y = -2
Both equations have the y value equal -2 when x = 3. Therefore, the overall solution is confirmed.
Answer:
Σ(-1)^kx^k for k = 0 to n
Step-by-step explanation:
The nth Maclaurin polynomials for f to be
Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......
The given function is.
f(x) = 1/(1+x)
Differentiate four times with respect to x
f(x) = 1/(1+x)
f'(x) = -1/(1+x)²
f''(x) = 2/(1+x)³
f'''(x) = -6/(1+x)⁴
f''''(x) = 24/(1+x)^5
To calculate with a coefficient of 1
f(0) = 1
f'(0) = -1
f''(0) = 2
f'''(0) = -6
f''''(0) = 24
Findinf Pn(x) for n = 0 to 4.
Po(x) = 1
P1(x) = 1 - x
P2(x) = 1 - x + x²
P3(x) = 1 - x+ x² - x³
P4(x) = 1 - x+ x² - x³+ x⁴
Hence, the nth Maclaurin polynomials is
1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n
= Σ(-1)^kx^k for k = 0 to n
For you to do area it is length times width.
Answer:
Y=-4x+6
Step-by-step explanation:
Step 1: Add -x to both sides.
X+0.25y+-x=1.5+-x
0.25y=-x+1.5
Step 2: Divide both sides by 0.25.
0.25y/0.25=-x+1.5/0.25
Y=-4x+6
Hope I helped
