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MakcuM [25]
3 years ago
6

How do I solve for X if I have something like this?(x+2)(1-x)= -4

Mathematics
1 answer:
lakkis [162]3 years ago
3 0

(x+2)(1-x)=-4

subtract 2 from both sides: x(1-x)=2

simplify:x-2x=2

subtract: -x=2

switch the negatives

x=-2

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the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?
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The other zero is

x =  - 10

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.


We were given that the axis of symmetry of the quadratic equation is
x =  - 3


We were also given that, one of the zeroes of the quadratic equation is
x = 4


Let the other zero of the quadratic equation be
x = p

,then, we apply the midpoint formula to find the value of
p

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,




\frac{x_1 + x_2}{2}  = axis \: of \: symmetry

We substitute to obtain,

\frac{p + 4}{2}  =  - 3



We multiply through by 2 to get,

p + 4 =  - 6



This implies that,

p =  - 6 - 4

p =  - 10




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