Answer: the pitch of the roof is 2/9
There are several shapes that fulfill these requirements. All involve to parallel rows of 4, then the other two trees forming a perpendicular for (using a tree from each of the other two rows).
E.g.
X X X X
X X X X
X
X
X X X X
X
X
X X X X
X X X X
X
X X X X
X
Answer0-4
Step-by-step explanation:
Lets say the race is x km long.
That means she ran 65% of x.
And that also means that 65% of x = 3
So 65%*x=3
65/100x=3
x=3*100/65
x=300/65
x=4.62
Answer:
![\bar X= \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
The reason is because we assume that each week have the same weight and replacing we got:
![\bar X= \frac{190+163+327+205}{4}= 221.25](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B190%2B163%2B327%2B205%7D%7B4%7D%3D%20221.25)
And the best option would be:
D. 221.25
Step-by-step explanation:
For this case we have the following data given
Week 1 2 3 4
Minutes 190 163 327 205
For this case we can find the mean with the following formula:
![\bar X= \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
The reason is because we assume that each week have the same weight and replacing we got:
![\bar X= \frac{190+163+327+205}{4}= 221.25](https://tex.z-dn.net/?f=%5Cbar%20X%3D%20%5Cfrac%7B190%2B163%2B327%2B205%7D%7B4%7D%3D%20221.25)
And the best option would be:
D. 221.25