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gizmo_the_mogwai [7]
2 years ago
9

Mily wrote the equation −3x=−2x−6

Mathematics
2 answers:
Daniel [21]2 years ago
8 0

Answer: x=6

Step-by-step explanation:

You have to get X on one side so you have to either add 2X to both sides or 3X to both sides depending on which one you would rather do and then you get 1X equals -6 and to get X by itself you have to divide by -1 which leaves you with -6 divided by -1 which equals 6

Dima020 [189]2 years ago
4 0

Answer:

x=6

Step-by-step explanation:

-3x=-2x-6

-3x+2x=-6

-x=-6

x=6

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The number of students in a chess club decreased from 27 to 11. What is
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Answer:

59.26.

Step-by-step explanation:

I think!

7 0
3 years ago
Two 5-year girls, Alyse and Jocelyn, have been training to run a 1-mile race. Alyse's 1 mile time A is approximately Normally di
tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

\bar {x}_1 = 13.5

\bar {x}_2 = 12

σ₁ = 2.5

σ₂ = 1.5

We set our α level at 0.05

Therefore, our critical z = ± 1.96

For n₁ = n₂ = 23, we have;

z=\dfrac{(13.5-12)-(0)}{\sqrt{\dfrac{2.5^{2} }{23}-\dfrac{1.5^{2}}{23}}} = 3.5969

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96

Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

8 0
3 years ago
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valkas [14]

Answer:

20 home runs left to hit.

Step-by-step explanation:

Ok so 100%/20% is 5. Increment 5 home runs until you get to 100%. So, 20% =5, 40% = 10, 80% = 15, and 100% = 20

7 0
2 years ago
Read 2 more answers
He first five multiples for the numbers 4 and 6 are shown below.
weeeeeb [17]

Answer:

12

Step-by-step explanation:

4 0
3 years ago
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As a​ follow-up to a report on gas​ consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f
kondor19780726 [428]

Answer:

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 96-1 = 95

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have T = 1.9855.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{5.6}{\sqrt{96}} = 0.57

Now, we multiply T and s

M = T*s = 1.9855*0.57 = 1.31

For the lower end of the interval, we subtract the mean by M. So 19.6 - 1.31 = 18.29

For the upper end of the interval, we add the mean to M. So 19.6 + 1.31 = 20.91

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

8 0
3 years ago
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