ABCD is a parallelogram Given
AE=CE, BE=DE <span>The diagonals of a parallelogram are bisect each other
</span>∠AEB=∠CED Vertical angles are congruent
ΔABE is congruent to ΔCDE SAS theorem<span>
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The value of Sin(a) suppose that Cos B = 0.68 in which case, a + B = 90° is; 0.68.
<h3>Trigonometry</h3>
First, when we have two angles, whose sum equals, 90°.
In essence, Since the algebraic sum of angles A and B is 90°;
By trigonometric identity;
Where; (90 - A) = B.
Therefore; Sin A = Cos B = 0.68.
Read more on trigonometry;
brainly.com/question/20519838
PV=FV/(1+i)^t
FV=7000, i=3.5%=0.035,t=9
put everything in the formula
PV=7000/(1+0.035)^9
PV=$5136.12
Answer: It's Congruent but not similar because the shape on top doesn't look like the bottom left.
Step-by-step explanation:
