Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
z is directly proportional to x: z = kx.
If z is directly proportional to x and inversely proportional to y, then z = Kx/y.
When x= 6 and y = 6, z is 12. Find the constant of proportionality, K:
12 = K(6/6), or K = 12
Then, in general, z = 12x/y.
What is z when x=13 and y=10? z = 12(13)/(10) = 15.6 (answer)
Answer:
5.1 days
Step-by-step explanation:

Cross Multiply

Divide both sides of the equation by 3.4

