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Mademuasel [1]
3 years ago
12

Is the relationship a function? {(1,4), (4,1), (1,5),(5,1)]

Mathematics
2 answers:
Ghella [55]3 years ago
3 0

Answer:

no

Step-by-step explanation:

hdjdjdnbdbdjddhhdhfhr r rjfnfn

weqwewe [10]3 years ago
3 0

Answer:

It is a function

Step-by-step explanation:

A linear function

x = y  - 3

and

x = y - 4

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The right triangle on the right is a scaled copy of the right triangle on the left. Identify
Mamont248 [21]
The scale factor is 3
7 0
1 year ago
What is the value of x in the equation 5(3x + 4) = 23
abruzzese [7]

5(3x+4)=23

15x+20=23

15x=23-20

15x=3

x=3/15

x=1/5=0.2

4 0
2 years ago
A business's total sales, including a 5% tax, were $23,152.81. Calculate the actual sales and sales tax liability
irina1246 [14]
If the total sales are $23152.81 and the sales tax is 5%, take the total sales divided by 1.05 $23152.81/1.05 = $22050.30 (gaves you the sales) to get the sales tax, subtract the total sales from the sales= Sales are $22050.30Tax is $1102.51 hope this helps :)
7 0
3 years ago
Read 2 more answers
For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?
DaniilM [7]
<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

                        x\neq 1

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]

Now, the determinant of this matrix is:

\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1

Hence,

-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1

4 0
3 years ago
I wiol mark you brainliest!!! Use the substitution method to solve the system of equations.
JulsSmile [24]

Answer: b. (6,27)

Step-by-step explanation:

y=5x- 3     x=6<---- put in the equation

y=5(6)-3 <------- mulitply 5 and 6

y=30-3 <---- subtracted

y= 27. <---- y value.

Answer being (6,27)

Hope it helps :)

5 0
3 years ago
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