The exponential growth function is P(t) = 6.38 million x (1.0238^t).
The population of the city in 2018 is 7.35 million.
The year the population would be 9 million is 14.46 years.
The doubling time is 29.12 years.
<h3>What is the exponential growth function?</h3>
FV = P (1 + r)^n
- FV = Future population
- P = Present population
- R = rate of growth
- N = number of years
6.38 million x (1.0238^t)
Population in 2018 = 6.38 million x (1.0238^6) = 7.35 million
Number of years when population would be 9 million : (In FV / PV) / r
(In 9 / 6.38) / 0.0238 = 14.46 years
Doubling time = In 2 / 0.0238 = 29.12 years
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Answer:
what is your problem im a kid
Answer:
Step-by-step explanation:
Direct variation problems can easily be solved with proportions, namely:
and cross multiply to get
2y = 20 so
y = 10
The first thing you should do for this case is to use the following table to perform the equation of a line:
y x
41,431 1995
48,729 2005
We have then that the line that best fits this data is
y = 729.8x - 1E + 06
Then, to know in what year the number of shopping centers reaches 80,000 we must replace this number in the equation of the line and clear x:
80000 = 729.8x - 1E + 06
Clearing x
x = (80000 + 1E + 06) / (729.8) = 1479.857495
nearest whole number
1480
This means that after 1480 years, 80000 shopping centers are reached.
Equivalently, this amount is reached in the year:
1480 + 1995 = 3475
In the year 3475
answer
(a) y = 729.8x - 1E + 06
(b) In the year 3475
