No. This is because the two smaller lengths must be greater than the largest length (7+3=10) this is less than 13 meaning the triangle won’t work
In order it goes like this
- 4^ x - 1 = 3^ (-x) - 2
- 3 x + 6 = 2^ x + 1
3^ x - 3 = 2 x - 2
so the question is the answer
Answer:
31q+15
Step-by-step explanation:
Answer:
2a(b^3 - 7b + 8)
Step-by-step explanation:
I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.
Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.
2a2b3 - 14ab + 16a
2(ab^3 - 7ab +8a)
2a(b^3 - 7b + 8)
