Answer:
By comparing the ratios of sides in similar triangles ΔABC and ΔADB,we can say that 
Step-by-step explanation:
Given that ∠ABC=∠ADC, AD=p and DC=q.
Let us take compare Δ ABC and Δ ADB in the attached file , ∠A is common in both triangles
and given ∠ABC=∠ADB=90°
Hence using AA postulate, ΔABC ≈ ΔADB.
Now we will equate respective side ratios in both triangles.
Since we don't know BD , BC let us take first equality and plugin the variables given in respective sides.
Cross multiply
Hence proved.
Answer:
The probability that exactly two have flaws is P (x=2) = 0.2376
Step-by-step explanation:
Here
Success= p= 0.15
Failure = q= 0.85
total number= n= 8
Number chosen = x= 2
Applying the binomial distribution
P (x=x) = nCx p^x(q)^n-x
P (x=2) = 8C2 0.15 ²(0.85)^8
P (x=2) = 0.2376
The success is chosen about which we want to find the probability. Here we want to find the probability that exactly two have flaws so success would be having flaws therefore p = 0.15
First divide bot sides of the formula by 1/2(3.14):-
2A / 3.14 = r^2
r = sqrt (2A/3.14)
Option m = 17
y = total cost of the service
m = number of miles run
y = 1.25 + 0.75 m
Equal the cost to the amount available by Henri
14 = 1.25 + 0.75m
Solve for m
m = (14 - 1.25)/0.75 = 12.75 / 0.75 = 17 miles.
I believe the answer is BC, AB, AC
