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3 years ago

8

Please help thank you

1 answer:

Makovka662 [10]3 years ago

6 0

1)
45x^3+5x
the GCF is 5x because that is a factor of both.
The answer would be 5x(9x^2+1)

2)
u^2-5u+6
factoring is finding what multiplies to the last number to add to the middle number. Those numbers are -3 and -2.
the answer would be (u-3)(u+2)

3)
m^2-49
difference of perfect squares
answer is (m+7)(m-7)

4)
x^5+4x^4+3x^3
GCF is x^3 so it's x^3(x^2+4x+3)
Factor that and it's x^3(x+3)(x+1)

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3 years ago

The sum of three numbers is 98 . The first number is 7 less than the second. The third number is 3 times the second. What are th

loris [4]

Answer:

14, 21, and 63

Step-by-step explanation:

we can set the three unknown numbers as x, y, and z

so

x + y + z =98

now we are given that the first (x) is seven less than the second (y)

x = y - 7

the third number (z) is three times the second (y)

z = 3y

since we have an equation for z and x in terms of y, we can plug it into the first equation and solve for y.

(y-7) + y + (3y) =98

y - 7 + y + 3y =98

y + y + 3y =105

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y=21

now that we know y, we can plug its value into either the second or the third equation to find x or z (I chose to find z first)

z = 3y

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7 0

4 years ago

irakobra [83]

A function can be represented by equations and tables

4 users are logged in by 9am
The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

$g(x) = \frac14 \sqrt{x - 3} + 3$

At 9am, x = 9.

So, we have:

$g(x) = \frac14 \sqrt{9 - 3} + 3$

$g(x) = \frac14 \sqrt{6} + 3$

Simplify

$g(9) = 3.6$

Approximate

$g(9) = 4$

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

$x - 3 = 0$

Solve for x

$x = 3$

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

$g(x) = \frac14 \sqrt{x - 3} + 3$

$g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3$

When x = 23, we have:

$g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4$

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0

3 years ago