Answer:
d = -1/3, 0
Step-by-step explanation:
Subtract the constant on the left, take the square root, and solve from there.
(6d +1)^2 + 12 = 13 . . . . given
(6d +1)^2 = 1 . . . . . . . . . .subtract 12
6d +1 = ±√1 . . . . . . . . . . take the square root
6d = -1 ±1 . . . . . . . . . . . .subtract 1
d = (-1 ±1)/6 . . . . . . . . . . divide by 6
d = -1/3, 0
_____
Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:
f(x) = (6x+1)^ +12 -13
We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.
1.9 = 1 9/10 in simplest form
Answer:


Step-by-step explanation:
A vector quantity is represented by 
where y = y-coordinate and x = x-coordinate
Since vector AB represents a vector in 3rd quadrant,
It starts from point A and ends at B,
Therefore, coordinates of B are (-9, -4)
= 
Similarly vector CD starts with C and ends at D in the 2nd quadrant,
Therefore coordinates of D will be (-5, 4)

Answer:

Step-by-step explanation:
The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

Please note that the names (
) and (
) are subjective and change depending on the angle one uses in the ratio. However the name (
) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.
In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent (
) ratio.

Substitute,

Inverse operations,


Simplify,


Answer:
b+10g-x
Step-by-step explanation:
3x-4x=x
New equation becomes:
b+10g-x