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3 years ago

4/14=6/? what is the missing number or what is the ?. nedd anser asap

Mathematics

1 answer:

BigorU [14]3 years ago

4 0

They both just have to simplify to the same thing, so the answer is 6/21

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Questio

Olenka [21]

Answer:

d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

(6d +1)^2 + 12 = 13 . . . . given

(6d +1)^2 = 1 . . . . . . . . . .subtract 12

6d +1 = ±√1 . . . . . . . . . . take the square root

6d = -1 ±1 . . . . . . . . . . . .subtract 1

d = (-1 ±1)/6 . . . . . . . . . . divide by 6

d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

4 0

3 years ago

1.9 as a mixed number in simplest form

Yuri [45]

1.9 = 1 9/10 in simplest form

5 0

2 years ago

Hey guys plz help meee<br><br>the answers have to be in numbers.

Licemer1 [7]

Answer:

$\overrightarrow{AB}=\frac{-9}{-4}$

$\overrightarrow{CD}=\frac{-5}{4}$

Step-by-step explanation:

A vector quantity is represented by $(\frac{y}{x})$

where y = y-coordinate and x = x-coordinate

Since vector AB represents a vector in 3rd quadrant,

It starts from point A and ends at B,

Therefore, coordinates of B are (-9, -4)

$\overrightarrow{AB}$ = $(\frac{-9}{-4})$

Similarly vector CD starts with C and ends at D in the 2nd quadrant,

Therefore coordinates of D will be (-5, 4)

$\overrightarrow{CD}=\frac{-5}{4}$

7 0

3 years ago

Help help help pls :)

kykrilka [37]

Answer:

$opposite\approx 70.02$

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Please note that the names ( $opposite$ ) and ( $adjacent$ ) are subjective and change depending on the angle one uses in the ratio. However the name ( $hypotenuse$ ) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent ( $tan$ ) ratio.