Answer: 11am
Step-by-step explanation:
To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:
20 = 20, 40, 60, 80, 100
30 = 30, 60, 90, 120, 150.
Here, the lowest common multiple is 60.
Therefore, we add 60 minutes to 10am. This will be:
= 10am + 1 hour
= 11 am
The next time that both buses leave at the same time would be 11am
2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
Answer:
A. 2(16+12)
Step-by-step explanation:
1. 2x16=32
2. 2x12=24
3. 32+24=56
