Using Pythagorean theorem c^2=a^2 + b^2, we can find the missing side b.
Put values in equation.
18^2 = 8^2 + b^2
324=64+b^2
Subtract 64 from both sides
260= b^2
Take square root.
2√65=b
or
b=16.12
Answer: b=2√65 Radical form. or b=16.12 Decimal form.
You just multiply them because “as” in the question means the same thing as “of” so it will be 7/16.
Answer:
3 1/11
Step-by-step explanation:
8 1/2 x 4/11
Change to an improper fraction
(2*8+1)/2 * 4/11
17/2 * 4/11
68 /22
Divide the top and bottom by 2
34/11
Change back to a mixed number
11 goes into 34 3 times with 1 left over
3 1/11
Answer:
Step-by-step explanation:
a) about the line y = 3
⇒ 
is the intersection point
So,
b) about the line x = 5
⇒ 
So,
![V = \int\limits^3_0\pi([5-0]^2-[5-y^2/9]^2)\:dy=\pi\int\limits^3_0(25-25+10y^2/9-y^4/81)\:dy=\\\\=\pi(10y^3/27-y^5/405)|^3_0=\pi(10-3/5)=\frac{47}{5} \pi](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E3_0%5Cpi%28%5B5-0%5D%5E2-%5B5-y%5E2%2F9%5D%5E2%29%5C%3Ady%3D%5Cpi%5Cint%5Climits%5E3_0%2825-25%2B10y%5E2%2F9-y%5E4%2F81%29%5C%3Ady%3D%5C%5C%5C%5C%3D%5Cpi%2810y%5E3%2F27-y%5E5%2F405%29%7C%5E3_0%3D%5Cpi%2810-3%2F5%29%3D%5Cfrac%7B47%7D%7B5%7D%20%5Cpi)
The U in the upper right corner stands for the universal set.
As universal set defined the set containing all objects or elements and of which all other sets are subsets. So, the answer is B.
