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Olin [163]
3 years ago
7

A service station checks Mr. Smith's radiator and finds it contains only 40% antifreeze. If the radiator holds 20 quarts and is

full, how many quarts must be replaced with pure antifreeze in order to bring it up to a required 80% antifreeze?
Mathematics
1 answer:
storchak [24]3 years ago
7 0

Answer:

8 quarts

Step-by-step explanation:

<u>Step One: Figure out how much 40% is by making an equation:</u>

<em>Since we are looking for a percentage, we use cross multiplication to find X.</em>

\frac{x}{20} = \frac{40}{100}

<u>Step Two: multiply 20 by 40 to start cross multiplying:</u>

<em>20 times 40 is 800, so replace the 40 by 800 in the equation.</em>

\frac{x}{20} = \frac{800}{100}

<u>Step Three: divide 800 by 100, and we will have X:</u>

<em>800/100=8</em>

<em><u>X=8 aka 8 quarts</u></em>

I hope this helps!

pls give thx and brainliest :D

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Answer:

1000

Step-by-step explanation:

3443-2476

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4 0
3 years ago
One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co
julsineya [31]

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

                                                                 = x + 0.5 x

                                                                 = 1.5 x

Therefore the amount of acid in first container =x \times \frac{30}{100} = 0.3 x

The amount of acid in second container =1.5x \times \frac{50}{100}  = 0.75x

Total amount of acid= 0.3x + 0.75x = 1.05 x

Total amount  of solution = x+1.5x = 2.5x

The amount of acid in third container is = \frac{1.05x}{2.5x} \times 100% %

                                                                     = 42%

4 0
3 years ago
Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
3 years ago
Read 2 more answers
Which<br> equation represents a line that passes through (-2, 4) and has a slope of 2/5?
pashok25 [27]

Answer:y - 4 = 2/5(x + 2)

Step-by-step explanation:

Mark me brainliest

4 0
2 years ago
Help me please and thank you
Oduvanchick [21]

Answer:

<h2>The required answer is 218 degree.</h2>

Step-by-step explanation:

∠AOB = 90 degree.

∠BOC = 52 degree.

Arc CDE = 180 degree, since CE is the diameter.

Hence, Arc EAC = 180 degree.

Besides, Arc EAC = Arc EA + Arc AB + Arc BC = Arc EA + 90 + 52 = Arc EA + 142.

Thus, Arc EA = 180 - 142 = 38 degree.

Arc ADC = 180 + 38 = 218 degree.

8 0
3 years ago
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