Every transaction has a double effect i.e Dr and cr
Answer: $144,936
Explanation:
First start by removing the initial debt from the initial basis so as not to inflate the basis.
= 118,800 - 11,880
= $106,920
That is the Initial basis void of debt.
Then add anything that will increase the basis and remove anything that will reduce the basis. Income and debt generally increase the basis while dividends or cash Distributions reduce them.
The Ending basis is therefore,
= Pre debt Initial basis + Partnership Income + ending debt + Nontaxable income - Cash Distribution
= 106,920 + 47,520 + 17,820 + 2,376 - 29,700
= $144,936
Barnaby's basis at the end of the tax year is $144,936.
Answer:
Federal communication commission
Explanation:
The organization which recently ruled that the internet service providers who could charge different rates for different types of users was the Federal Communication Commission.
Hope this helps.
Good luck and Thank you.
In order for employees to take initiative is to give them something to work for. For example, you can offer a reward for all his/hers hard work. Another example would be the employee of tge month benefits, and dont just give them a better parking spot. One of the best ways for employees to take intiative is just by showing them some respect and showing you care about them.
Answer:
The answer is below
Explanation:
The marginal revenue R'(t) = 
and the marginal cost C'(t) = 140 - 0.3t.
The total profit is the difference between the total revenue and total cost of a product, it is given by:
Profit = Revenue - Cost
P(T) = R(T) - C(T)
P(T) = ∫ R'(T) - C'(T)
Hence the total profit from 0 to 5 days is given as
![P(T) = \int\limits^0_5 {(R'(T)-C'(T))} \, dt= \int\limits^0_5 {(100e^t-(140-0.3t))} \, dt\\ \\P(T)= \int\limits^0_5 {(100e^t-140+0.3t))} \, dt\\\\P(T)= \int\limits^0_5 {100e^t} \, dt- \int\limits^0_5 {140} \, dt+ \int\limits^0_5 {0.3t} \, dt\\\\P(T)=100\int\limits^0_5 {e^t} \, dt- 140\int\limits^0_5 {1} \, dt+0.3 \int\limits^0_5 {t} \, dt\\\\P(T)=100[e^t]_0^5-140[t]_0^5+0.3[\frac{t^2}{2} ]_0^5\\\\P(T)=100(147.41)-140(5)+0.3(12.5)=14741-700+3.75\\\\P(T)=14045](https://tex.z-dn.net/?f=P%28T%29%20%3D%20%5Cint%5Climits%5E0_5%20%7B%28R%27%28T%29-C%27%28T%29%29%7D%20%5C%2C%20dt%3D%20%5Cint%5Climits%5E0_5%20%7B%28100e%5Et-%28140-0.3t%29%29%7D%20%5C%2C%20dt%5C%5C%20%5C%5CP%28T%29%3D%20%5Cint%5Climits%5E0_5%20%7B%28100e%5Et-140%2B0.3t%29%29%7D%20%5C%2C%20dt%5C%5C%5C%5CP%28T%29%3D%20%5Cint%5Climits%5E0_5%20%7B100e%5Et%7D%20%5C%2C%20dt-%20%5Cint%5Climits%5E0_5%20%7B140%7D%20%5C%2C%20dt%2B%20%5Cint%5Climits%5E0_5%20%7B0.3t%7D%20%5C%2C%20dt%5C%5C%5C%5CP%28T%29%3D100%5Cint%5Climits%5E0_5%20%7Be%5Et%7D%20%5C%2C%20dt-%20140%5Cint%5Climits%5E0_5%20%7B1%7D%20%5C%2C%20dt%2B0.3%20%5Cint%5Climits%5E0_5%20%7Bt%7D%20%5C%2C%20dt%5C%5C%5C%5CP%28T%29%3D100%5Be%5Et%5D_0%5E5-140%5Bt%5D_0%5E5%2B0.3%5B%5Cfrac%7Bt%5E2%7D%7B2%7D%20%5D_0%5E5%5C%5C%5C%5CP%28T%29%3D100%28147.41%29-140%285%29%2B0.3%2812.5%29%3D14741-700%2B3.75%5C%5C%5C%5CP%28T%29%3D14045)
