Question

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely with 196 grams of H2 SO4?
A) 1
B) 2
C) 0.5
D) 4

Answer 1

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $H_2SO_4$:-  

Mass of $H_2SO_4$ = 196 g

Molar mass of $H_2SO_4$ = 98 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{196\ g}{98\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 2\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

Mass = Moles*molar mass = $4\times 40\ g$ = 160 g