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3 years ago

Does hydrogen have similar physical properties to alkali metals?

Chemistry

1 answer:

Komok [63]3 years ago

6 0

Answer:

Explanation:

<h3>because it contain 1 electron in its outermost shell</h3>

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What volume of nitrogen gas at STP is produced when 68.2 g of trinitrotoluene, C7H5(NO2)3 reacts?

lys-0071 [83]

Answer:

10.07 L is the volume for the produced N₂

Explanation:

This is a question for the Ideal Gases Equation:

P . V = n . R . T

In STP conditions, the pressure is 1 atm and the T° is 273K

Let's determine the moles of produced N₂ by the decomposition of TNT

The reaction is:

2 C₇H₅(NO₂)₃ (s) → 7 C (s) + 7 CO (g) + 3 N₂ (g) + 5 H₂O (g)

We convert the mass to moles (mass / molar mass)

68.2 g . 1 mol / 227.13 g = 0.300 moles

Ratio is 2:3. 2 moles of TNT can produce 3 moles of N₂

Then, 0.300 moles will produce (0.300 . 3) / 2 = 0.450 moles

We replace data:

1 atm . V = 0.450 mol . 0.082 L.atm/mol.K . 273K

V = (0.450 mol . 0.082 L.atm/mol.K . 273K) / 1 atm

V = 10.07 L

4 0

4 years ago

How many neutrons are in Br-85

Travka [436]

There are 45 neutrons

3 0

3 years ago

Nsity VVS

Kazeer [188]

Answer:

<h2>The answer is 1.99 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of acid = 60.19 g

volume = 30.2 mL

The density is

$density = \frac{60.19}{30.2} \\ = 1.993046357...$

We have the final answer as

Hope this helps you

8 0

3 years ago

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?

Vladimir79 [104]

P: ?
V: 35,5L = 35,5 dm³
n: 0,54 mol
R: 83,14 hPa·dm³/mol·K
T: 223K
..................
pV = nRT
p = nRT/V
p = (0,54×83,14×223)/35,5
p = 282,02 hPa

4 0

3 years ago

Write the net cell equation for this electrochemical cell. Phases are optional. Do not include the concentrations. Co ( s ) ∣ ∣

Tatiana [17]

Answer: The overall equation will be $Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)$

Explanation:

The representation is given by writing the anode on left hand side followed by its ion with its molar concentration. It is followed by a salt bridge. Then the cathodic ion with its molar concentration is written and then the cathode.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Anode : $Co(s)\rightarrow Co^{2+}(aq)+2e^{-}$

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Cathode : $Ag^+(aq)+e^{-1}\rightarrow Ag(s)$ $\times 2$

The number of electrons lost must be equal to the number of electrons gained , thus overall equation will be :

$Co(s)+2Ag^+(aq)\rightarrow Co^{2+}(aq)+Ag(s)$

5 0

3 years ago