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3 years ago

Y=-3x + 6

Mathematics

1 answer:

slamgirl [31]3 years ago

5 0

Answer:

(-1, 9) (he x value is placed first).

Step-by-step explanation:

y = -3x + 6

y = 9

Substitute y = 9 into the first equation:

9 = -3(x) + 6

-3x = 9 - 6

-3x = 3

x = -1.

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Mumz [18]

*The missing image is attached with the answer*

The correct answer is: Height = h =5 units

Explanation:
a = 6 = Smaller base
b = 10 = Larger base
h = height

Area = A = (a + b)h/2 = 40

Plug in the values in the above equation:
h = (2*40)/(6+10)
h = 5 units

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Anna007 [38]

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3 years ago

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2x^3 + 3x^2 -11x -6 divided by x - 2

Gnesinka [82]

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

x=2

therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

= 2*8 + 3*4 - 11*2 - 6

= 16 + 12 - 22 - 6

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3 years ago

Simplify (Are all division) 2+4i 3i 3+2i 4+i 2i^11

Alla [95]

$We\ know:\ i=\sqrt{-1}\to i^2=-1$

$\dfrac{2+4i}{3i}=\dfrac{2+4i}{3i}\cdot\dfrac{3i}{3i}=\dfrac{6i+12i^2}{9i^2}=\dfrac{6i+12(-1)}{9(-1)}\\\\=\dfrac{6i-12}{-9}=\dfrac{2i-4}{-3}=\dfrac{4}{3}-\dfrac{2}{3}i$

$\dfrac{3+2i}{4+i}=\dfrac{3+2i}{4+i}\cdot\dfrac{4-i}{4-i}=\dfrac{(3+2i)(4-i)}{4^2-i^2}\\\\=\dfrac{(3)(4)+(3)(-i)+(2i)(4)+(2i)(-i)}{16-(-1)}=\dfrac{12-3i+8i-2i^2}{16+1}\\\\=\dfrac{12+5i-2(-1)}{17}=\dfrac{12+5i+2}{17}=\dfrac{14+5i}{17}=\dfrac{14}{17}+\dfrac{5}{17}i$

$2i^{11}=2i^{10+1}=2i^{10}i^1=2i^{2\cdot5}i=2i(i^2)^5=2i(-1)^5=2i(-1)=-2i$

$Used:\ (a+b)(a-b)=a^2-b^2$

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