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kari74 [83]
4 years ago
6

Consider the function below, f (x) =x^3 + 2x^2-x-2,

Mathematics
1 answer:
Snowcat [4.5K]4 years ago
6 0

Answer:

The x-intercepts are at x = -2, x = -1, and x = 1.

The y-intercept is at y = -2.

Step-by-step explanation:

(a) Create a table containing a few values of x and y.

<u> x </u>  <u> y  </u>

-3  -8

-2   0

-1   0

0  -2

 1   0

(b) Plot the points on your graph

They should look something the graph below.  

The x-intercepts are at x = -2, x = -1, and x = 1.

The y-intercept is at y = -2.

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