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igomit [66]
4 years ago
12

" alt="y {?}^{2} - 18y + 81" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
guajiro [1.7K]4 years ago
7 0
\bf y^2-18y+81\implies \stackrel{FOIL}{(y-9)(y-9)}
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(1 point) a tank contains 1060 l of pure water. a solution that contains 0.06 kg of sugar per liter enters the tank at the rate
kirill115 [55]
(a) There is 0 kg of sugar in the tank at the beginning since it contains pure water at the start. The sugar only comes from the solution.

(b)

S' = f(t,S) = \left(0.06 \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) - \left(\dfrac{S}{1060} \dfrac{\text{kg}}{\text{L}}\right)\left(9\dfrac{\text{L}}{\text{min}}\right) \ \Rightarrow \\ \\ S' = 0.54 \text{ kg}/\text{min} - \dfrac{9S}{1060}

So yes, you enter S' = 0.54 - (9S/1060)

(c)

\displaystyle\frac{dS}{dt} = 0.54 - \frac{9S}{1060} \ \Rightarrow\ \frac{dS}{dt} = \frac{572.4 - 9S}{1060}\ \Rightarrow\ \dfrac{dS}{572.4 - 9S} = \frac{1}{1060} dt\ \Rightarrow \\ \\
\int \dfrac{dS}{572.4 - 9S} = \int \frac{1}{1060} dt\ \Rightarrow\textstyle\ -\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t + C \\ \\
S(0) = 0 \ \Rightarrow\ -\frac{1}{9}\ln|572.4 - 0| = \frac{1}{1060}(0) + C\  \Rightarrow\ C = -\frac{1}{9} \ln 572.4

-\frac{1}{9}\ln|572.4 - 9S| = \frac{1}{1060}t  -\frac{1}{9} \ln 572.4\ \Rightarrow \\ \\
\ln|572.4 - 9S| = \ln 572.4 - \frac{9}{1060}t \ \Rightarrow \\ \\
|572.4 - 9S| = e^{\ln 572.4 - 9t/1060}\ \Rightarrow \\ \\
572.4 - 9S= \pm 572.4 e^{-9t/1060}\ \Rightarrow \\ \\
S = \frac{-1}{9}\left(-572.4 \pm 572.4 e^{-9t/1060}\right)

But only (+) satisfies S(0) = 0

S= -\frac{1}{9}\left(-572.4 + 572.4 e^{-9t/1060}\right) \\ \\
S= 63.6 - 63.6 e^{-9t/1060}\text{ kg}

Enter
in S = 63.6 - 63.6 * e^(-9t/1060)

3 0
3 years ago
Pedro was stocking up on uniforms for the new
Kazeer [188]

Answer

5

Step-by-step explanation:

141.75 - 68 = 73.75

73.75 / 14.75 = 5

8 0
3 years ago
198 sq.yd. 8 sq. ft. x 7 =
vichka [17]

Answer:

Step-by-step explanation:

Give the data

198 sq.yd × 8 sq ft ×7

Note that we have two unit of measurement which are yd and ft and 7 is just a constant

So we need to convert them,

Then, 1 yd = 3ft

Also notice that they are square.

Then square both sides of the comparison

(1 yd)² = (3 ft)²

1 sq.yd = 9 sq.ft

Then, back to our question,

198 sq.yd × 8 sq ft ×7

Let covert to ft

198 sq.yd× (9 sq.ft/1 sq.yd) ×8 sq.ft×7

sq.yd cancels out

99,792 sq.ft × sq.ft

99,792 ft⁴

Let convert to yd

198 sq.yd × 8 sq ft ×7

198 sq.yd×8 sq.ft (1 sq.yd / 9sq.ft )×7

1,232 sq.yd × sq.yd

1,232 yd⁴

4 0
3 years ago
Read 2 more answers
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Answer:

The area of triangle P is 12cm squared. The mathematical term for quadlilateral Q is called a Kite.

Step-by-step explanation:

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3 years ago
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To be honest I would need a picture to answer this question
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