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3 years ago

A chord divides a circle into

1 answer:

5 0

<span>A chord divides a circle into 2 segments.

A major segment and a minor segment.

If the chord passes through the center of the circle, then it divides the circle into equal segments.</span>

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One side of a regular pentagon measures 0.8 meters. What is the perimeter of the regular pentagon

topjm [15]

5 (the sides) x 0.8 = 4 meters

3 0

2 years ago

The formula for the area of a rhombus is A = a equals StartFraction one-half EndFraction d 1 d 2.d1d2, where d1 and d2 are the l

AlexFokin [52]

The two equivalent equations are d₁= 2a/d₂ and d₂= 2a/d₁ , Option 2 and 5 is the right answer.

<h3>What is a Rhombus ?</h3>

Rhombus is a quadrilateral with all the sides equal to each other.

It is given that d₁ and d₂ are the lengths of the diagonals.

and Area = a

a = (1/2) d₁ * d₂

2a = d₁ * d₂

d₁ * d₂ = 2a

It can be written as

d₁= 2a/d₂

a = (1/2) d₁ * d₂

d₁ * d₂ = 2a

d₂= 2a/d₁

Therefore Option 2 and 5 are the correct answer.

The options of this question are:

1. d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2A/d₁

To know more about Rhombus

brainly.com/question/27870968

#SPJ1

3 0

2 years ago

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers

dalvyx [7]

Answer:

4 pitchers

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

step 1

Find the volume of the cylinder with height 9 inches and radius r

substitute the given values

$V_1=\pi r^{2}(9)$

$V_1=9\pi r^{2}\ in^3$

step 2

Find the volume of the cylinder with height 9 inches and radius 2r

substitute the given values

$V_2=\pi (2r)^{2}(9)$

$V_2=36\pi r^{2}\ in^3$

step 3

we know that

The volume of the cylinder 1 can fill a certain pitcher,

The volume of the pitcher is the same that the volume of cylinder 1

therefore

the number of pitchers that can be filled by the second cylinder is equal to divide the volume of the second cylinder by the volume of the first cylinder

$\frac{36\pi r^{2}}{9\pi r^{2}}=4\ pitchers$