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Leviafan [203]
2 years ago
9

Find the area A of the sector of a circle of radius 90 in formed by central angle 1/6 radian.

Mathematics
1 answer:
miv72 [106K]2 years ago
5 0

Answer:

2121 in^{2} Rounded to the nearest inch.

Step-by-step explanation:

A = \pi r^{2}  Is the formula for a circle, but we only have a portion of a circle so we will have to adjust the formula for a part of the circle.

A = \frac{\frac{\pi }{6} }{2\pi } \pi r^{2}  The \frac{\pi }{6} is the part of the circle and the whole circle is 2\pi

\frac{\frac{\pi }{6} }{2\pi } is the same as \frac{\pi }{6}÷\frac{2\pi }{1} Which is the same as \frac{\pi }{6} x \frac{1}{2\pi } Which is the same a \frac{1}{12}

A = \frac{1}{12}\pi90^{2}

A = \frac{1}{12}(3.14)(90)(90) = 2119.5.  When you use the \pi on your calculator you get a slightly different number.  This is due to rounding.

A = 2120.575041

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Answer:

a) Option D) 0.75

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Step-by-step explanation:

We are given the following in the question:

Percentage of students who choose Western riding = 35%

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P(j) = 0.50

Percentage of students who choose both dressage and jumping = 20%

P(d \cap j) = 0.20

Percentage of students who choose Western and dressage = 10%

P(w \cap d) = 0.10

Percentage of students who choose Western and jumping = 0%

P(w \cap j) = 0

Thus, we can say

P(w \cap j \cap d) = 0

Formula:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

a) P(student chooses dressage or jumping)

P(d \cup j) = P(d) + P(j) -p(d \cap j)\\= 0.45 + 0.50-0.20 = 0.75

b) P(student chooses neither dressage nor Western riding)

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3 years ago
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Step-by-step explanation:

1 4/6-5/6=?

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