7.35m3 4.2 m long 50 cm deep width

If $4000 is borrowed at a rate of 16% interest

Gemiola [76]

Answer:

(a) $7492

(b) $10,253

(c) $14,032

Step-by-step explanation:

As we know, the final Amount can be calculated with the formula for compound interest,

A = P(1 + \frac{r}{n} )^{nt}

where,

A = Final Amount due

P = Initial principal amount borrowed

r = rate of interest in decimal

n = number of times applied per time period

t = total time period

Now, according to the given data,

(a) in 4 years ;-

⇒ $A = 4000(1 + \frac{0.16}{4} )^{4(4)}$

⇒ $A = 7492$

(b) in 6 years ;-

⇒ $A = 4000(1 + \frac{0.16}{4} )^{4(6)}$

⇒ $A = 10,253$

(c) in 8 years ;-

⇒ $A = 4000(1 + \frac{0.16}{4} )^{4(8)}$

⇒ $A = 14,032$

6 0

3 years ago

Which list shows all the subset of the set (c,g,n)?

Tresset [83]

Answer:A is a subset of D

Step-by-step explanation:

Because A has what it is contained D

3 0

3 years ago

Clara would like to buy a toy for her baby sister that sells for

trapecia [35]

So all you need to do is to multiply 12.49 by 1.13 ( since 1.00 is the price and 0.13 is the added tax rate), which gives you $14.11

8 0

3 years ago

A TV station claims that 38% of the 6:00 - 7:00 pm viewing audience watches its evening news program. A consumer group believes

Elena L [17]

Answer:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

$\hat p=\frac{282}{830}=0.340$ estimated proportion of people that regularly watch the TV station’s news program

$p_o=0.38$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:

Null hypothesis: $p\geq 0.38$

Alternative hypothesis: $p < 0.38$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .

3 0

3 years ago

Please answer 6 and 7

sleet_krkn [62]

Answer:

ok aaj SGD Hv the best of my friends in a couple days of a sudden in

8 0

2 years ago