PLS HELP ME !! MARKING BRAINLIST IF CORRECT!! :) HELP WITH BOTH PROBLEMS

What is the answer to 45 − (−28) =

Lorico [155]

Step-by-step explanation:

You can also write it as 45+28.

In English, a double negative is when two negative words are used in the same sentence.

A double negative in Math is when you have a scenario like this. For example, 1-(-1) is also equal to 1+1.

So 45+28 is 73.

Hope it helps!

3 0

3 years ago

Read 2 more answers

The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q

Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

$\frac{\sum f}{4}=\frac{100}{4}=25$

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF) $_{p}$ = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

$=34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75$

The value of first quartile is 34.75.

Q₃ is at the position:

$\frac{3\sum f}{4}=\frac{3\times100}{4}=75$

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF) $_{p}$ = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

$=44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83$

The value of third quartile is 44.83.

Then the inter-quartile range is:

$IQR = Q_{3}-Q_{1}$

$=44.83-34.75\\=10.08$

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

$P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}$

$=\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89$

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0

3 years ago

1. Use the cosine and sine functions to express the exact coordinates of P in terms of angle θ.

Luden [163]

Answer:

For a point defined bt a radius R, and an angle θ measured from the positive x-axis (like the one in the image)

The transformation to rectangular coordinates is written as:

x = R*cos(θ)

y = R*sin(θ)

Here we are in the unit circle, so we have a radius equal to 1, so R = 1.

Then the exact coordinates of the point are:

(cos(θ), sin(θ))

2) We want to mark a point Q in the unit circle sch that the tangent has a value of 0.

Remember that:

tan(x) = sin(x)/cos(x)

So if sin(x) = 0, then:

tan(x) = sin(x)/cos(x) = 0/cos(x) = 0

So tan(x) is 0 in the points such that the sine function is zero.

These values are:

sin(0°) = 0

sin(180°) = 0

Then the two possible points where the tangent is zero are the ones drawn in the image below.

7 0

3 years ago

You have purchased a new warehouse. To finance the purchase, you’ve arranged for a 25-year mortgage for 75 percent of the $4,200

Cerrena [4.2K]

\begin{aligned}Payment=183000\\ \cos t=4200000\cdot 0,75\% =3150000=c\\ Payment=C\dfrac {\left( 1+i\right) ^{n}\cdot i}{\left( 1+i\right) ^{n}-1}\\ n=25years\times \dfrac {12manths}{1year}=300months\\ 18300=3150000\cdot \dfrac {\left( 1+i\right) ^{300}\cdot i}{\left( 1+i\right) ^{300}\cdot i}\\ i=0,0041\\ i is the monhly interest_{i}\\ i\times 12months=APR\\ APR=0,0123=1,23%\end{aligned}

7 0

3 years ago

Sophia exchanged 1000 U.S. dollars for the South African currency which is called the rand. The exchange rate was 8.05 rand to 1

saw5 [17]

Answer:

Sophia gets 7,150

Step-by-step explanation:

6 0

2 years ago