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Dmitrij [34]
3 years ago
5

Here is an interesting exponential function,

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

The number 1 raised to any number will always equal 1.

So the Y values in the chart are all 1.

Then the plot would be a straight horizontal line at Y1, so it is neither growth or decay.

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What is another way to write9×200
user100 [1]
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 200
8 0
4 years ago
For the given functions, (a) express dw/dt as a function of t, both by using the chain rule and by expressing w in terms of t an
ch4aika [34]

By the chain rule,

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

We have

w=7ye^x-\ln z\implies\begin{cases}\dfrac{\partial w}{\partial x}=7ye^x\\\\\dfrac{\partial w}{\partial y}=7e^x\\\\\dfrac{\partial w}{\partial z}=-\dfrac1z\end{cases}

and

\begin{cases}x=\ln(t^2+1)\\y=\tan^{-1}t\\z=e^t\end{cases}\implies\begin{cases}\dfrac{\mathrm dx}{\mathrm dt}=\dfrac{2t}{t^2+1}\\\\\dfrac{\mathrm dy}{\mathrm dt}=\dfrac1{t^2+1}\\\\\dfrac{\mathrm dz}{\mathrm dt}=e^t\end{cases}

Putting everything together, we get

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{14ye^xt}{t^2+1}+\dfrac{7e^x}{t^2+1}-\dfrac{e^t}z

x=\ln(t^2+1), so e^x=e^{\ln(t^2+1)}=t^2+1, and z=e^t, so \frac{e^t}z=1.

\dfrac{\mathrm dw}{\mathrm dt}=14yt+7-1

\dfrac{\mathrm dw}{\mathrm dt}=14t\tan^{-1}t+6

Then when t=1, the derivative has a value of \frac{7\pi}2+6.

6 0
3 years ago
Please answer this correctly
cluponka [151]

Answer:

2:30pm

Step-by-step explanation:

7 0
3 years ago
HELP I'M BEING TIMED I WILL GIVE 5 points... a thankyou...5 stars... and a brainliast if correct.
Alexus [3.1K]

Answer:

i think its a or d but im hoorible at math so if its wrong im sorry

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Where does the graph of y= sin x from x = 0 to x = 2n1 start?
stepladder [879]

Answer:

Step-by-step explanation:

when x=0,sin x=0

when x=30° or π/6

sinx=1/2=0.5

when x=45° or π/4

sin x=√2/2≈1.414/2≈0.707

when x=60° or π/3

sinx=√3/2≈1.732/2≈0.866

when x=90° or π/2

sin x=1

when x=120° 2π/3

sin 120=sin (180-60)=sin 60 ≈0.866

when x=135° or 3π/4

sin 135=sin (180-45)=sin 45≈0.707

when x=150° or 5π/6

sin 150=sin (180-30)=sin 30=0.5

when x=180 or π

sin 180=sin(180-0)=sin 0=0

when x=210° or 7π/6

sin 210=sin (180+30)=-sin 30=-0.5

when x=225° or 5π/4

sin x=sin (180+45)=-sin 45≈-0.707

when x=240° or 4π/3

sin 240=sin (180+60)=-sin 60≈ -0.866

when x=270° or 3π/2

sin 270=sin (180+90)=-sin 90=-1

when x=300° or  5π/3

sin 300=sin(360-60)=-sin 60≈ -0.866

when x=315°or 7π/4

sin 315=sin (360-45)= -sin 45≈ -0.707

when x=330° or 13π/6

sin 330=sin (360-30)= -sin 30 =-0.5

when x=360 or 2π

sin (360)=sin (360+0)=sin 0=0

plot all these points on the graph,you get the reqd. graph.

you see it starts on (0,0)

6 0
4 years ago
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