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viktelen [127]
3 years ago
6

The graph of this system of equations is used to solve 4x^2-3x+6=2x^4-9x^3+2x What represents the solution set?

Mathematics
2 answers:
hammer [34]3 years ago
8 0

We are given equation : 4x^2-3x+6=2x^4-9x^3+2x.

Let us write it in form of a system of two equations:

y= 4x^2-3x+6 and

y =2x^4-9x^3+2x

Let us put those equations on a graphing calculator to get the graphs of the above system of equations.

<h3>From the graph, we can see that y-intercepts are : (0,0) and (0,6).</h3><h3>x-intercepts are (-0.45, 0) (0,0), (0.5,0) and (4.45,0)</h3><h3>y-coordinate of the intersection points : 14.69.</h3><h3>x-coordinates of the intersection points : -1.15</h3>

Alex17521 [72]3 years ago
8 0

Answer:

The solution is x-coordinate of the intersection points

D is correct

Step-by-step explanation:

Given: 4x^2-3x+6=2x^4-9x^3+2x

We need to find solution of given equation.

First we make system of equation and then find intersection point of graph.

y_1=4x^2-3x+6

y_2=2x^4-9x^3+2x

Now we draw the graph of system of equation using graphing calculator.

Please see the attachment for graph.

In graph both equation intersect at two points.

Point of intersection gives the solution of the equation.

x-coordinate of the intersection of graph gives the solution because function depends on x.

Hence, The solution is x-coordinate of the intersection points

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The answer is 0.31

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<u>Old Method                                       New Method                          .</u>

Mean                      73.5625                  Mean            75.70588

Standard Error        3.143736             Standard Error  2.923994

Median                    72                          Median            75

Mode                       90                          Mode               64

Standard deviation  12.57494           Standard deviation 12.05594

Sample Variance     158.1292            Sample Variance     145.3456

Kurtosis                     -1.14544              Kurtosis                   -0.76646

Skewness                 0.171025             Skewness                0.091008

Range                       39                        Range                      41

Minimum                   55                        Minimum                 56

Maximum                  94                        Maximum                 97

Sum                          1177                        Sum                        1287

Count                         16                         Count                      17

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: μNew< μOld

Alternative hypothesis: μNew > μOld

Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected if the mean difference between sample means is too small.

Formulate an analysis plan. For this analysis, the significance level is 0.05. Using sample data, we will conduct a two-sample t-test of the null hypothesis.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

SE=\sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} } \\\\SE=4.29

DF = 31

t = \frac{(x_1-x_2)-d}{SE} \\\\t = - 0.4997

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The observed difference in sample means produced a t statistic of - 0.499. We use the t Distribution Calculator to find P(t < - 0.499) = 0.311

Therefore, the P-value in this analysis is 0.311.

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