The best way I can explain the elimination method is, it's a method where you either add or subtract equations in order to get rid of a variable.
Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere
The differential of V with respect to r is:
dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
W=A\L
Divide L from both sides
The L in the right cancels out
Answer:
Step-by-step explanation:
V = L*w*h
L = 3
w = 2
h = ?
V = 24
24 = 2*3 * h Combine the right
24 = 6* h Divide both sides by 6
24/6 = 6h/6
4 = h