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lions [1.4K]
3 years ago
13

The domain of y = csc x is given by x≠nπ. True or False?

Mathematics
2 answers:
Nuetrik [128]3 years ago
4 0

Answer:

True          

Step-by-step explanation:

Given : The domain of y = csc x is given by x\neq n\pi

The given statement is true.

Because,  y = csc x

y =\frac{1}{sinx}{

sinx is defined for \forall x\varepsilon \mathbb{R}

csc xis defined whenever sinx\neq 0\rightarrow x\neq n\pi,\forall n\varepsilon \mathbb{Z}

Hence the domain of y is allx\varepsilon \mathbb{R}: x\neq 0\rightarrow x\neq n\pi,\forall n\varepsilon \mathbb{Z}

Therefore, the statement is true as the domain of y = csc x is x\varepsilon \mathbb{R}: x\neq 0\rightarrow x\neq n\pi,\forall n\varepsilon \mathbb{Z}


Travka [436]3 years ago
3 0

Answer:

True Ap ex

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Hello!

The objective is to test if the new production method used to manufacture aircraft altimeters has a standard deviation greater than 32.2 ft (δ>32.2)

A random sample of n= 12 aircraft altimeters was taken and the measurement errors of each altimeter were recorded.

The variable of interest is X: measuring error of an aircraft altimeter that was manufactured using the new method.

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H₁: δ² > 1036.84 (δ>32.2)

α: 0.05

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∑X²= 43416

S²= 1/(n-1)[∑X²-(∑X)²/n]= 1/11[43416-(280)²/12]= 3352.97

X^2_{H_0}= \frac{(11*3352.97)}{1036.84}= 35.57

This test is one tailed  to the right, this means that, using the critical value approach, that you will reject the null hypothesis to high values of X²X^2_{n-1;1-\alpha }= X^2_{11;0.95}= 19.675

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If X^2_{H_0} ≥ 19.675, the decision is to reject the null hypothesis

If X^2_{H_0} < 19.675, the decision is to not reject the null hypothesis.

The calculated value is greater than the critical value, the decision is to reject the null hypothesis.

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I hope this helps!

*-*-*-*-*-*-*

Full text

Test the given claim. Assume that a simple random sample is selected from a normally distributed population. Use either the P value method or the traditional method of testing hypotheses. Company A uses a new production method to manufacture aircraft altimeters. A simple random sample of new altimeters resulted in errors listed below. Use a 0.05 level of significance to test the claim that hte new production method has errors with a standard deviation greater than 32.2 ft which was the standard deviation for the old production method. If it appears that the standard deviation is greater does the new production method appear to be better or worse than the old method? Should the company take any action?

-40, 78,-24,-70,-40,15,19,54,-9,-51,-106,-106

What are the null and alternative hypotheses?

A. standard deviation =32.2 ft standard deviation greater than 32.2 ft

B. standard deviation greather than 32.2 ft standard deviation= 32.2 ft

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E. standard deviation is less than 32.2 ft stanard deviation equal 32.2 ft

F. standard deviation is equal to 32.2 ft standard deviation less than 32.2 ft

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Determine the critical value= use a comma to seperate

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The variation appears to be ______ than in the past so the new method could be _______ because there will be more ______ in altimeters. Therefore the company _______ take immediate action to reduce the variation.

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