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3 years ago

What is the position of b on the number line below

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

I can’t seem to see the line below

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Seventy thousand in standard form

lys-0071 [83]

Answer: 70,000

Step-by-step explanation:

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3 years ago

Read 2 more answers

he length of a rectangle is three times the width. The perimeter is 240 inches. Find the length and the width.

sammy [17]

Answer:

Length = 90 inch.

width = 30 inch

Let width of the rectangle = x inch.

So the length = 3x inch.

Perimeter = 2(length + width) = 2 (3x + x) = 8x.

So,

length = 3x = 3(30) = 90 inch.

width = x = 30 inch

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2 years ago

What are the x and the y in this function

Marianna [84]

Answer:

X = 3

Y = all real numbers

Step-by-step explanation:

x is the input

y is the output

The equation would be x = 3

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2 years ago

How many 1 / 4 pound hamburgers can be made from 9 / 12 pound of meat?<br> More questions to come

Oxana [17]

Answer: Hi

Step-by-step explanation:

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4 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

3 years ago