Make f(x) = y
f(x)= -1/8 (4) ^x+3 +6
y = -1/8 (4) ^x+3 +6
y-intercept is when the function crosses the y-axis, and the y-axis is always where x = 0
y = -1/8 (4) ^x+3 +6
or was the equation instead:
???????
Because in that case it's totally different, so here goes...
Therefore, yes it is correct that the y-intercept lies at the point (0, -2)
f(x)= -1/8 (4) ^x+3 +6
y = -1/8 (4) ^x+3 +6
y-intercept is when the function crosses the y-axis, and the y-axis is always where x = 0
y = -1/8 (4) ^x+3 +6
or was the equation instead:
???????
Because in that case it's totally different, so here goes...
Therefore, yes it is correct that the y-intercept lies at the point (0, -2)