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Anna007 [38]
3 years ago
8

Plzz help

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

3200 Divide 384 by .12 That equals 3200

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A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles. HINT [See Example 7.] H
lapo4ka [179]

Answer: 8

Step-by-step explanation:

Given: A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles.

Total marbles other than green = 8

Total marbles other than green and yellow = 6

Then the number of sets of seven marbles include at least one yellow one but no green ones:-

^{2}C_1\times^{6}C_6+ ^2C_2\times^6C_5\\\\= 2\times 1+1\times6\\\\=2+6=8

Number of sets of seven marbles include at least one yellow one but no green ones = 8

3 0
3 years ago
The data below are the ages and systolic blood pressures (measured in millimeters of mercury) of 9 randomly selected adults. Age
Ipatiy [6.2K]

Answer:

156

Step-by-step explanation:

Given the data:

Age (X) :

38

41

45

48

51

53

57

61

65

Pressure(Y) :

116

120

123

131

142

145

148

150

152

From the data, we could obtain a regression equation to mod the data Given using a linear regression calculator :

The regression equation obtained is :

y = 1.48769X + 60.46103

Using the model, the predicted blood pressure for a person aged 64 will be :

y = 1.48769(64) + 60.46103

y = 95.21216 + 60.46103

y = 155.67319

y = 156 (nearest whole number)

3 0
2 years ago
A $1508 award is shared equally by 8 people. What is each persons share of the award
andreev551 [17]

Answer:

$188.50

Step-by-step explanation:

i got this answer by dividing $1,508 by 8 and you would get 188.5 which would turn into $188.50 and that is how much each person would get.

I hope this helps.

6 0
3 years ago
Read 2 more answers
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
What is the distance from W to X?
Flauer [41]

Answer:

The answer is 35 miles.

Step-by-step explanation:

Let's assume that the distance from W to Y is x miles

Distance from W to X is 70 % of x =0.7*x

Given distance from X to Y is 15 miles.

x-15=0.7x

x-0.7x=15

0.3x=15

x=15/0.3

x=50miles

Thus the distance from W to Y is 50 miles and the distance from W to X is 50-15=35 miles

3 0
2 years ago
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