3 years ago

Rotate the vector -5,7 180 degrees about the origin

Mathematics

1 answer:

Helen [10]3 years ago

3 0

okkkk the vector is not rotating I tried ms

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3 years ago

The line m has a slope of 2/3.Which line described below is the only line that could be parallel to line m?

ANEK [815]

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3 years ago

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grandymaker [24]

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3 years ago

Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108

Novosadov [1.4K]

Answer:

$3a^2 - 36a + 108 = (\sqrt{3}a - 6\sqrt{3} )^2$

Step-by-step explanation:

$3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2$

$so, a = \sqrt{3} a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}$

Therefore ,

$3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2 = (\sqrt{3}a - 6\sqrt{3} )^2$

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3 years ago

Help please! I need to write 4y =-3x + 12 in standard form, find the y-intercept of the previous equation, as an ordered pair, a

damaskus [11]

Answer:

$-3x+4y=12\\y-intercept: (0,3)\\x-intercept: (-4,0)$

Step-by-step explanation:

The standard form of a linear equation is $ax+by=c$ , where $a$ , $b$ , and $c$ are constants in the equation.

Based on the equation you have provided, the standard form would be $-3x+4y=12$ , where $a=-3, b=4, c=12$ .

To find the y-intercept, set $x=0$ .

$-3(0)+4y=12\\0+4y=12\\4y=12\\y=\frac{12}{4} =3$

Therefore, the y-intercept is $(0,3)$ .

Do the same thing for the x-intercept, but this time with $y=0$ .

$-3x+4(0)=12\\-3x+0=12\\-3x=12\\x=\frac{12}{-3} =-4$

Therefore, the x-intercept is $(-4,0)$ .

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3 years ago