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Mandarinka [93]
3 years ago
11

How are plants in a sunny meadow and sulfur bacteria in a deep sea vent alike?

Biology
2 answers:
yan [13]3 years ago
6 0
Well it’s obvious that they both use Photosynthesis to make there own food, and also they both use chemosynthesis the produce there own food. Very simple. :)
iren2701 [21]3 years ago
3 0

They both produce carbohydrates and oxygen .They both use photosynthesis to make their own food. They both use chemo synthesis to produce their own food.

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How can the presence of one species benefit another in the same ecosystem
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The different species present in an ecosystem make the ecosystem balanced.  The species of an ecosystem interact with one another in one form or the other. For example, the presence of a plant species will provide food for the abundant types of herbivores present in an ecosystem. A predator might feed on many types of preys. Hence, the presence of different preys will reduce the chances of a species from becoming wiped out from the ecosystem. Hence, all the organisms in an ecosystem are dependent on another in some way or the other.

8 0
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22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit
mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square (X^2):

X^2  =  \frac{(O - E)^2}{E} where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The X^2 is calculated thus:

Phenotype            O               E                             X^2

  1                          88            164.81            \frac{(88 - 164.81)^2}{164.81} = 35.80

  2                          62             54.94            \frac{(62 - 54.94)^2}{54.94} = 0.91

  3                           62             54.94              \frac{(62 - 54.94)^2}{54.94} = 0.91

  4                            81              18.31               \frac{(81 - 18.31)^2}{18.31} = 214.64

Total X^2 = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

X^2 tabulated  = 7.815

<em>The calculated </em>X^2<em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently.        </em>

4 0
3 years ago
What do solid and hazardous wastes have in common?
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