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Step2247 [10]
4 years ago
15

Complete the equation of the line.

Mathematics
1 answer:
mestny [16]4 years ago
7 0

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:

y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

According to the statement, the line goes through the following points:

(x_ {1}, y_ {1}) :( 1,1)\\(x_ {2}, y_ {2}) :( 0, -3)

We found the slope:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-3-1} {0-1} = \frac {-4} {- 1 } = 4

Thus, the equation is of the form:

y = 4x + b

We substitute one of the points and find b:

-3 = 4 (0) + b\\b = -3

Thus, the equation is of the form:

y = 4x-3

Answer:

y = 4x-3

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26\% \ of \ 125= \frac{26}{100}*125= \\\\= \frac{26}{4}*5= \\\\ =\frac{13}{2}*5= \\\\ =\boxed{\frac{65}{2}\to32.5}
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What fraction plus another fraction = -7/36
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-14/36 + 7/36= -7/36
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Use the coordinate plane to plot the points (6, 0) and (0, 5). Which statement is true? (0, 5) is located on the x-axis. (0, 5)
m_a_m_a [10]

Answer:

(6, 0) is located on the x-axis

Explanation:

For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.

"(0, 5) is located at the origin" is not true because the origin is at (0, 0).

"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.

"(6, 0) is located at the origin" is not true because the origin is at (0, 0).

6 0
3 years ago
What is the equation of the line that passes through the point (-2, 0) and has a slope of -2?​
liq [111]

Answer:

y=-2(x+2)

Step-by-step explanation:

plug in(-2,0) into y-y1=m(x-x1)

y=m(x+2)

slope =m=-2

y=-2(x+2)

8 0
3 years ago
Simplify the square root of 3 times the fifth root of 3.
bogdanovich [222]

Answer:

<h2><em>Three to the three fifths power.</em></h2>

Step-by-step explanation:

The given expression is

\sqrt{3\sqrt[5]{3} }

To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:

\sqrt[n]{x^{m}}=x^{\frac{m}{n}}

Applying the property, we have:

\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}

Now, we multiply exponents:

(3(3)^{\frac{1}{5}})^{\frac{1}{2}}\\3^{\frac{1}{2}}3^{\frac{1}{10}}

Then, we sum exponents to get the simplest form:

3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}}  \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }

Therefore, the right answer is <em>three to the three fifths power.</em>

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4 years ago
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