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3 years ago

12

Select the correct answer. What is the inverse of function f?

1 answer:

zubka84 [21]3 years ago

7 0

the correct answer is b and a

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Answer the very simple question below!

zalisa [80]

Answer: 14

Step-by-step explanation: just go to the opposite side of the interger and plz Brainlest would be much appreciated.

5 0

3 years ago

Read 2 more answers

2. In segment AC, the midpoint is B.<br> If segment AC = 2 and AB = 7x-3, find x.

Scorpion4ik [409]

X=1
midpoint is half way, half of 2 is 1

4 0

3 years ago

To the nearest degree, what is m A

Simora [160]

Answer:

53°

Step-by-step explanation:

With reference angle A

perpendicular (p) = 9.6

base (b) = 7.2

Now

tan A = p / b

tan A = 9.6 / 7.2

A = tan^ - 1 ( 9.6 / 7.2)

A = 53°

Hope it will help :)❤

6 0

3 years ago

The area of the shaded square is square inches. The length of the unshaded rectangle is inches. The estimated value of the lengt

Marina CMI [18]

11.8 and 156.8

because its relevant

4 0

3 years ago

Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (84, 13) lies

tia_tia [17]

Answer:

$\sin \theta = 0.153$ , $\cos \theta = 0.988$ , $\tan \theta = 0.155$ , $\cot \theta = 6.462$ , $\sec \theta = 1.012$ , $\csc \theta = 6.538$

Step-by-step explanation:

Let be the point $(x,y)$ , the six trigonometric functions of the angle are represented by following formulas:

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$ (1)

$\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}$ (2)

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

$\cot \theta = \frac{1}{\tan \theta} = \frac{x}{y}$ (4)

$\sec \theta = \frac{1}{\cos \theta} = \frac{\sqrt{x^{2}+y^{2}}}{x}$ (5)

$\csc \theta = \frac{1}{\sin \theta} = \frac{\sqrt{x^{2}+y^{2}}}{y}$ (6)

If we know that $x = 84$ and $y = 13$ , then the values of the six trigonometric functions is:

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$

$\sin \theta = 0.153$

$\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}$

$\cos \theta = 0.988$

$\tan \theta = \frac{y}{x}$

$\tan \theta = 0.155$

$\cot \theta = \frac{x}{y}$

$\cot \theta = 6.462$

$\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}$

$\sec \theta = 1.012$

$\csc \theta = \frac{\sqrt{x^{2}+y^{2}}}{y}$

$\csc \theta = 6.538$

4 0

3 years ago