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3 years ago

What is the answer to 11 over 7 in improper fractions

Mathematics

2 answers:

Marianna [84]3 years ago

6 0

If u change it to a proper fraction it would be a mixed number and the mixed number is 1 4/7

ioda3 years ago

5 0

If its improper fraction is 11/7 if you want the mixed number its 1 4/7

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Worth all my points plus Brainlist answer number 14 please it’s due in three hours

Lana71 [14]

Answer:

Answer below

Step-by-step explanation:

2.08

2.082

2.8

2.82

√8 (it's 2.8284)

3 0

3 years ago

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Please tell me the answer as quick as possible! Stuck here badly :(

olga2289 [7]

63degrees

Step-by-step explanation:

there are multiple ways to do this

for one, angle a = angle e (corresponding angles)

angle f + angle e = 180 degrees (angles on a straight line)

angle f = 180 degrees - angle e where angle e = angle a = 117degrees

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3 years ago

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

4 years ago

Consider the probability that at least 93 out of 154 CDs will not be defective. Assume the probability that a given CD will not

Yuki888 [10]

Answer:

0.5962

Step-by-step explanation:

Given that :

p = 61% = 0.61

q = 1 - p = 1 - 0.61 = 0.39

n = 154 ; x = 93

Using the binomial probability formula :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

P(x>=93) = p(x=93)+p(x=94)+...+p(x=n)

P(x>= 93) = 0.59619

P(x>= 93) = 0.5962

7 0

3 years ago

I need help please and thank you

sergeinik [125]

Try googling it , sorry

8 0

3 years ago