X=4 and y=6
For this, you should use simultaneous equations
The area, in square inches, outside the smaller region, but inside the larger region is 99π
<h3>How to determine the area, in square inches, outside the smaller region, but inside the larger region?</h3>
The given parameters are:
Radius, r1 = 1 inch
Radius, r2 = 10 inches
The area, in square inches, outside the smaller region, but inside the larger region is calculated as
Area = π(R^2 - r^2)
This gives
Area = π(10^2 - 1^2)
Evaluate the difference
Area = 99π
Hence, the area, in square inches, outside the smaller region, but inside the larger region is 99π
Read more about area at:
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The answer: 9 and 10 or 8 and 9
8x8=64
9x9=81
10x10=100
They are close by 18 so If it’s only an answer I would go for 8 and 9
Answer:
Step-by-step explanation:
use pythagorean theorem a^2 + b^2 = c^2
a = 6, b = 8
6^2 + 8^2 = c^2
100 = c^2
c = -10
since it cant really be negative, the distance becomes 10.
