R = 2 / (1 + sin <span>θ)
Using the following relations:
R = sqrt (x^2 + y^2)
sin </span>θ = y/R
<span>
R = 2 / (1 + y/R)
R</span>(1 + y/R<span>) = 2
</span><span>R + y = 2
R = 2 - y
sqrt(x^2 + y^2) = 2 - y
Squaring both sides:
x^2 + y^2 = (2 - y)^2
x^2 + y^2 = 4 - 4y + y^2
x^2 + 4y - 4
</span>
Answer:
Step-by-step explanation:
Isn’t this mathematics not science
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>
How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
To learn more about common differences refer to:
brainly.com/question/1486233
#SPJ4
Answer:
His money earned $36 after 3 months
Step-by-step explanation:
* Lets revise the rules of simple interest
- Simple Interest Equation (Principal + Interest)
A = P(1 + rt)
- Where:
• A = Total amount (principal + interest) future amount
• P = Principal Amount
• I = Interest Amount
• r = Rate of Interest per year in decimal; r = R/100
• t = Time Period involved
* To calculate the interest I use the formula
I = P × r × t
* Lets solve the problem
- The rate is annual
- The interest calculated after 3 months
∴ I = P × R/100 × t/12
∵ P = $3600.00
∵ R = 4%
∵ t = 3 month
∴ I = 3600.00 × 4/100 × 3/12 = $36
* His money earned $36 after 3 months