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3 years ago

(3x^2-15d) - (-10x^2-4d)

Mathematics

2 answers:

ElenaW [278]3 years ago

6 0

(3x^2-15d) - (-10x^2-4d) = 13x^2-11d

Hope this helps!!

kirill [66]3 years ago

4 0

Yehhhh man whattt hee said im just trynnna get more points

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Solve and graph the inequality 6 + 3n ≤40

Kazeer [188]

6+3n≤40
Use inverse operations i.e.
4x+2<10
-2 -2
4x<8
4*x/4<8/4
x<2

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2 years ago

One third divided by 4

MA_775_DIABLO [31]

Answer:

1/12

I used keep change flip.

7 0

3 years ago

Read 2 more answers

A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i

goldfiish [28.3K]

Answer:

P(t) = 100·2.3^t
529 after 2 hours
441 per hour, rate of growth at 2 hours
5.5 hours to reach 10,000

Step-by-step explanation:

It often works well to write an exponential expression as ...

value = (initial value)×(growth factor)^(t/(growth period))

(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...

P(t) = 100·2.3^t

(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours

(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t

P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour

(d) We want to find t such that ...

P(t) = 10000

100·2.3^t = 10000 . . . substitute for P(t)

2.3^t = 100 . . . . . . . . divide by 100

t·log(2.3) = log(100)

t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000

6 0

3 years ago

30+ Points!!! 5. Solve the following inequalities. a) 2 log3x – 2 logx3 -3 <0

Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

$\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}$

$2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)$

$\mathrm{Simplify}$

$-2logx^3-3$

$\mathrm{Add\:}3\mathrm{\:to\:both\:sides}$

$-2logx^3-3+3$

$\mathrm{Simplify}$

$-2logx^3$

$Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)$

$\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)$

$\mathrm{Simplify}$

$2lx^3og>2\log ^3\left(x\right)-3$

$\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0$

$\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\$

$\mathrm{Simplify}$

$g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0$

Step-by-step explanation:

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2 years ago

What is a separable differential equation? How do you solve it?

Alexus [3.1K]

A separable differential equation is a first-order differential equation in which the expression for dy/dx can be factored as a function of x times a function of y,
that is, dy/dx = g(x) f(y). We can solve this equation by integrating both sides of the equation dy/f(y) = g(x)dx.

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2 years ago