<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span><span>=<span><span><span><span>2<span>x^3</span></span>+<span>6x</span></span>+152
</span><span>x+4</span></span></span><span>=<span><span><span>2<span>(<span>x+4</span>)</span></span><span>(<span><span><span>x^2</span>−<span>4x</span></span>+19</span>)
</span></span><span>x+4</span></span></span><span>=<span><span><span>2<span>x^2</span></span>−<span>8x</span></span>+<span>38= is the answer</span></span></span>
How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?
1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.
2. All 4 answers add up to 105ml.
3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution
4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution
Answer:
1
Step-by-step explanation:
Distance covered by a car in 1 gallon = 32.6miles Distance covered by a car in 12.3gallons = 32.6*12.3 =400.98miles
