Answer:
C. 16 cm
Step-by-step explanation:
Top side: 2 + 4 = 6
Right side: 1 + 1 = 2
Bottom: 2 + 4 = 6
Left side: 1 + 1 = 2
6+6+2+2 = 16 cm.
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
The answer is A because I said so
Answer: The tangent of the larger acute angle is 4/3 or 1⅓
Step-by-step explanation: if the sides of the right angled triangle are given as 3, 4 and 5 respectively, then the hypotenuse is 5 and the longer of the other two sides is 4. The angle facing the side measuring 4 is your reference angle, and that is the larger of the other two acute angles (see attachment)
Tan X = opposite/hypotenuse
Tan X = 4/3
Tan X = 1⅓