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2 years ago

Find the perimeter of the shape in the image A) 8cm B) 12cm C) 16cm D) 20cm

Mathematics

1 answer:

ivanzaharov [21]2 years ago

4 0

Answer:

C. 16 cm

Step-by-step explanation:

Top side: 2 + 4 = 6

Right side: 1 + 1 = 2

Bottom: 2 + 4 = 6

Left side: 1 + 1 = 2

6+6+2+2 = 16 cm.

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A city has a population of 310,000 people. Suppose that each year the population grows by 9%. What will the population be after

Leno4ka [110]

Answer: 644,800

Step-by-step explanation:

This can also be solved using the terms of Arithmetic Progressions.

Let the 13 years be number of terms of the sequences (n)

Therefore ;

T₁₃ = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000

9% of 310,000 = 9/100 x 310,000

= 27,900

so the common difference (d)

d = 27,900

Now substitute for the values in the formula above and calculate

T₁₃ = 310,000 + ( 13 - 1 ) x 27,900

= 310,000 + 12 x 27,900

= 310,000 + 334,800

= 644,800.

The population after 13 years = 644,800.

3 0

2 years ago

The measure of 2WXZ is 100°.<br> What is the measure of ZYXZ?

Rom4ik [11]

Answer:

a) 69.99

b) .20%

Your welcom ,.hb

Step-by-step explanation:

4 0

2 years ago

It takes Oliver 30 minutes to walk to school everyday a distance of 1.5 miles. what is Oliver speed in miles per hour

Olegator [25]

1.5 miles/30 minutes is your unit rate. If you multiply the rate by 2 you would get 3 miles/hour.

So your final answer would be 3 miles per hour.
Hope this helps.

5 0

2 years ago

Read 2 more answers

More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh

Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = $\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx$

= $\int_{-1.34}^{1.34}(5x^{2}-9)dx$

= $[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}$

= $[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]$

= $[-4.01+12.06-4.01+12.06]$

= 16.1 unit²

6 0

3 years ago

What does the 50th term of this arithmetic sequence: 29,32,35,38

frozen [14]

Answer:

176

Step-by-step explanation:

First term (a) = 29

Common difference (d) = 32 - 29 = 3

For calculating the 50th term , n = 50

Now

$t_{50} = a + ( n - 1) d\\t_{50} = 29 + ( 50 - 1 ) *3\\ t_{50} = 29 + 147\\t_{50} = 176$

hope it will help :)

3 0

2 years ago