All categories

3 years ago

Find the perimeter of the shape in the image A) 8cm B) 12cm C) 16cm D) 20cm

Mathematics

1 answer:

ivanzaharov [21]3 years ago

4 0

Answer:

C. 16 cm

Step-by-step explanation:

Top side: 2 + 4 = 6

Right side: 1 + 1 = 2

Bottom: 2 + 4 = 6

Left side: 1 + 1 = 2

6+6+2+2 = 16 cm.

You might be interested in

PLEASE HELP

kirza4 [7]

Answer:

- 2/5

Step-by-step explanation:

Answer

Have an nice day and good luck

4 0

3 years ago

Read 2 more answers

Tuesday Describe the shape resulting from the cross section of the roll of cookie dough.

Rasek [7]

I might be wrong but I believe the shape of the cookie dough when cut is a cylinder

4 0

3 years ago

Read 2 more answers

Angela can complete 3 RCA problems in 2 minute.how many problems during 2 hours of tutoring?

Taya2010 [7]

Well how many minutes are in an hour? 60. 60/2 is 30, so she can complete 30 problems in an hour. Since it's 30 for one hour, that means she can solve 60 in 2 hours.

Don't forget to rate this answer the Brainliest!

3 0

3 years ago

Geometry math question no Guessing and Please show work thank you

Cloud [144]

here two given sides are 10 and 6,

We use the rule of triangle here:

sum of two sides> third side

checking for each option

Option A: AC=4

4+6>10, 10>10 (false)

So AC cannot be equal to 4, option A is answer.

3 0

3 years ago

The population of a certain species of insect is given by a differentiable function P, where P(t) is the number of insects in th

Step2247 [10]

Answer:

$\frac{dP}{dt} \ =\ \frac{1}{5}P$

Step-by-step explanation:

Given

Variation: Directly Proportional

Insects = 10 million when Rate = 2 million

i.e. $P = 10\ million$ when $\frac{dP}{dt} = 2\ million$

Required

Determine the differential equation for the scenario

The variation can be represented as:

$\frac{dP}{dt} \ \alpha\ P$

Which means that the rate at which the insects increase with time is directly proportional to the number of insects

Convert to equation

$\frac{dP}{dt} \ =\ k * P$

$\frac{dP}{dt} \ =\ kP$

Substitute values for $\frac{dP}{dt}$ and P

$2\ million = k * 10\ million$

Make k the subject

$k = \frac{2\ million}{10\ million}$

$k = \frac{2}{10}$

$k = \frac{1}{5}$

Substitute $\frac{1}{5}$ for k in $\frac{dP}{dt} \ =\ k * P$

$\frac{dP}{dt} \ =\ \frac{1}{5}* P$

$\frac{dP}{dt} \ =\ \frac{1}{5}P$

8 0

3 years ago