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Pavlova-9 [17]
3 years ago
15

>PLS HELP< WILL GIVE BRAINLIEST

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer: It would be the third one, but a more accurate equation would be 2πrh+2πr^2

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Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
4 years ago
Giả thiết X là biến ngẫu nhiên X~N(µ, σ^2) thì P( |X-µ| &gt;3,05*σ ) sẽ là
svp [43]

Answer:

,luvxieixeqbxeixbwibiblccucucx

Step-by-step explanation:

  1. h hccylbs f
  2. qvdjvjeflnd
  3. nwlxlwbxaabx
  4. emvfvten
7 0
3 years ago
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