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sp2606 [1]
3 years ago
8

Emily has 300 books if Frank were to double the number of books that he now owns he would still have fewer than Emily has

Mathematics
2 answers:
lozanna [386]3 years ago
7 0

math matical sentence


Artist 52 [7]3 years ago
5 0
He has <150 (hope that's what you're looking for!)
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What is X? combined with 10x^2
nordsb [41]

Answer:

20 lel. whwhwhw

Step-by-step explanation:

HQHWWNWJW

3 0
3 years ago
If m varies directly as p, and m=5 when p=7, what is the constant of variation?
Tanzania [10]
For direct relations, we can write:
m = kp; k is the constant of proportionality.
5 = 7k
k = 5/7
The constant of variation is 5/7.
5 0
3 years ago
Read 2 more answers
Let the demand function for a product be q = 100 - 2p. the inverse demand function of this demand function is:_______
Westkost [7]

The inverse demand function of the given demand function is <u>p = 50 - q/2</u>.

A graph that depicts the relationship between a product's price and demand is called a demand curve. On a demand graph, the horizontal axis represents the amount desired, while the vertical axis represents the product's price.

The price is a function of the quantity required when there is an inverse demand curve. The inverse of a demand curve indicates that variations in the amount required cause changes in price levels. The formula for calculating the demand curve for a product yields the graph of an inverse demand curve.

Given demand function: q = 100 - 2p.

To find the inverse demand function, we find the inverse of the equation, by isolating p, to get:

q = 100 - 2p,

or, 2p = 100 - q,

or, p = 100/2 - q/2,

or, p = 50 - q/2.

Thus, the inverse demand function of the given demand function is <u>p = 50 - q/2</u>.

Learn more about inverse functions at

brainly.com/question/3831584

#SPJ4

3 0
1 year ago
Plzz anyone solve all answers plzzzzzzzz​
algol13

You posted a lot of problems here. In the future please only post one problem at a time. Thank you.

I'll do the first two problems to get you started. Hopefully it will help you finish off the rest of the questions.

==========================================

Problem 1

{18, a, b, -3} is an arithmetic sequence or arithmetic progression (AP).

This means we have some number d added on to each term to get the next term.

first term = 18

second term = first term + d = 18+d = a

third term = second term + d = (18+d)+d = 18+2d = b

fourth term = third term + d = (18+2d)+d = 18+3d = -3

----

Let's solve that last equation for d

18+3d = -3

18+3d-18 = -3-18

3d = -21

3d/3 = -21/3

d = -7

----

The value d = -7 tells us to add -7 to each term to get the next term. In other words, we subtract 7 from each term to get the next term

first term = 18

second term = first term + d = 18+d = 18+(-7) = 18-7 = 11

third term = second term + d = 11+d = 11+(-7) = 11-7 = 4

fourth term = third term + d = 4+d = 4+(-7) = 4-7 = -3

----

We see that a = 11 and b = 4 are the second and third terms respectively.

Therefore, a+b = 11+4 = 15

-------------

<h3>Answer: 15</h3>

==========================================

Problem 2

A multiple of 4 is in the form 4*n for some integer n, ie n is a whole number.

We want to know which values of 4*n are between 10 and 250.

----

Divide both 10 and 250 by 4 to get the following

10/4 = 2.5

250/4 = 62.5

If n = 2, then 4*n = 4*2 = 8 is not between 10 and 250; however n = 3 will make 4*n = 4*3 = 12 to be between 10 and 250. We see that n = 3 is the smallest possible allowed value.

If n = 62, then 4*n = 4*62 = 248 is between 10 and 250; while n = 63 will make 4*n too big because 4*63 = 252. The largest n can get is n = 62

----

The question posed in question 2 is equivalent to asking the following: "How many values are in the set {3, 4, 5, ..., 60, 61, 62}?"

You could count all of the values in the set, but that exercise is very tedious busywork. There's a much faster way. First lets consider the set below

{a, a+1, a+2, ..., b-2, b-1, b}

where a,b are integers. Basically this set starts at 'a', counts up until we get to 'b'. The handy formula

c = b-a+1

will provide the exact count of values in the set {a, a+1, a+2, ..., b-2, b-1, b}

----

In this case, a = 3 and b = 62, making

c = b-a+1

c = 62-3+1

c = 60

There are 60 values in the set {3, 4, 5, ..., 60, 61, 62}

There are 60 multiples of four that are between 10 and 250.

-------------

<h3>Answer: 60</h3>
4 0
3 years ago
Which expressions are equivalent to z + (z + 6)?
katrin2010 [14]

Answer:

z=3 because in the 2(z+3) is like (z+2)+(z+6)

3 0
3 years ago
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