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Anarel [89]
3 years ago
6

The table shows information about all students doing GCSE's at a school.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

it's 3/5

Step-by-step explanation:

\frac{240}{400}  \frac{ \div }{ \div }  {4}  =  \frac{6}{10}  \frac{ \div }{ \div } 2 =  \frac{3}{5}

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Solve for x: 3x+6>-15 x=?
kati45 [8]

Answer:

x>-7

Step-by-step explanation:

4 0
2 years ago
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What are the zero(s) of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E%7B2%7D-36x%20%7D%7Bx-9%7D" id="TexFo
Contact [7]

Answer:

D

Step-by-step explanation:

The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:

0 = 4 {x}^{2}  - 36x

I will use the quadratic formula:

\frac{ 36  +  \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{  36 + 36}{8}  = 9

Therefore, x = 9 is a 0. Let's check with subtracted root now:

\frac{ 36   -    \sqrt{ {36}^{2}  - 4(4)(0)} }{2(4)}  \\  \frac{ 36  -  36}{8}  =  0

It appears 0 is also a root.

Therefore, the answer is D.

7 0
3 years ago
Given that f(x)=x^2+3x-28f(x)=x
spayn [35]

9514 1404 393

Answer:

  x^2 +4x -21

Step-by-step explanation:

Substitute the given expressions and simplify.

  f(x) + g(x)

  = (x^2 +3x -28) +(x +7)

  = x^2 +(3+1)x +(-28 +7)

  = x^2 +4x -21

6 0
3 years ago
3)Find the GCF and LCM of 10 and 28. Show your work.<br><br> HELP LAST QUESTION!!!!!
soldier1979 [14.2K]

Answer:

GCF=2 LCM=140

Step-by-step explanation:

8 0
2 years ago
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hichkok12 [17]

Answer:

<h2>use the required formulas please !</h2>
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3 years ago
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